Resposta:
[tex]a)k - \frac{273}{5} = \frac{f - 32}{9} [/tex]
[tex] \frac{330 - 273}{5} = \frac{f - 32}{9} [/tex]
[tex] \frac{57}{5} = \frac{f - 32}{9} [/tex]
[tex] \frac{11.4}{ {}^{1} } = \frac{f - 32}{9} [/tex]
[tex]f - 32 = 102.6[/tex]
[tex]f = 102.6 + 32[/tex]
[tex]f = 134.6 \: fahrenheit[/tex]
[tex]b) \frac{c}{5} = \frac{f - 32}{9} [/tex]
[tex] \frac{26}{5} = \frac{f - 32}{9} [/tex]
[tex] 5.2 \times \frac{f - 32}{9} = \frac{5.2}{ {}^{1} } = \frac{f - 32}{9} [/tex]
[tex]f - 32 = 46.8[/tex]
[tex]f = 46.8 + 32[/tex]
[tex]f = 78.8 \: fahrenheit[/tex]
[tex]c) \frac{f - 32}{9} = \frac{c}{5} [/tex]
[tex] \frac{1234 - 32}{9} = \frac{c}{5} [/tex]
[tex] \frac{1202}{9} = \frac{c}{5} [/tex]
[tex] \frac{133.5}{ {}^{1} } = \frac{c}{5} [/tex]
[tex]c = 667.5 \: celsius[/tex]
[tex]d) \frac{f - 32}{9} = \frac{c}{5} [/tex]
[tex] \frac{f - 32}{9} = \frac{ - 74}{5} [/tex]
[tex] \frac{f - 32}{9} = \frac{14.8}{ {}^{1} } [/tex]
[tex]f - 32 = - 133.2[/tex]
[tex]f = - 133.2 \: + \: 32 [/tex]
[tex]f - 101 {}^{0} \: fahrenheit [/tex]
[tex]e)k = c + 273[/tex]
[tex]k = 884 + 273[/tex]
[tex]k = 1.157 \: kelvin[/tex]
Explicação:
