Resposta:
x²-5×+6=0 a = 1 b = -5 c = 6
Δ = [tex]b^{2} -4.a.c[/tex]
Δ = [tex](-5)^{2} -4.1.6[/tex]
Δ = [tex]25-24[/tex]
Δ = [tex]1[/tex]
x = -b ± √Δ
2.a
x = -(-5) ± √1
2.1
x = 5 ± 1
2
Agora faz o [tex]x^{I} ,x^{II}[/tex] (X linha um e x linha dois).
[tex]x^{I} = \frac{5+1}{2} = \frac{6}{2} = 3[/tex]
[tex]x^{II} = \frac{5-1}{2} = \frac{4}{2} =2[/tex]
x²-8×+12=0 a = 1 b = -8 c = 12
Δ [tex]=b^{2} -4.a.c[/tex]
Δ [tex]=(-8)^{2} -4.1.12[/tex]
Δ [tex]= 64-48[/tex]
Δ [tex]=16[/tex]
x = -b ± √Δ
2.a
x = -(-8) ± √16
2.1
x = 8 ± 4
2
[tex]x^{I}[/tex] [tex]=\frac{8+4}{2} =\frac{12}{2} =6[/tex]
[tex]x^{II}[/tex][tex]=\frac{8-4}{2} =\frac{4}{2} =2[/tex]
x² + 2x - 8 = 0 a = 1 b = 2 c = -8
Δ [tex]=b^{2} -4.a.c[/tex]
Δ [tex]=(2) -4.1.(-8)[/tex]
Δ [tex]=2-32[/tex]
Δ = [tex]30[/tex]
x = -b ± √Δ
2.a
x = -(2) ±√30
2.1
x = -2 ± 5,4
2
[tex]x^{I} = \frac{-2+5,4}{2} = \frac{3}{2} = 1,5[/tex]
[tex]x^{II} = \frac{-2-5,4}{2} = \frac{-7}{2} = -3,5[/tex]
