Resposta:
[tex]\textsf{Leia abaixo}[/tex]
Explicação passo a passo:
[tex]\sf{P(-2;3)\:\:\:\:\:Q(6;1)}[/tex]
[tex]\sf{d_{PQ} = \sqrt{(x_P - x_Q)^2 + (y_P - y_Q)^2}}[/tex]
[tex]\sf{d_{PQ} = \sqrt{(-2 - 6)^2 + (3 - 1)^2}}[/tex]
[tex]\sf{d_{PQ} = \sqrt{(-8)^2 + (2)^2}}[/tex]
[tex]\sf{d_{PQ} = \sqrt{64 + 4}}[/tex]
[tex]\sf{d_{PQ} = \sqrt{68}}[/tex]
[tex]\sf{d_{PQ} = \sqrt{2^2.17}}[/tex]
[tex]\sf{d_{PQ} = 2\sqrt{17}}[/tex]
[tex]\mathsf{r = \dfrac{d_{PQ}}{2} = \dfrac{\not2\sqrt{17}}{\not2} = \sqrt{17}}[/tex]
[tex]\mathsf{C\left(\dfrac{x_P + x_Q}{2};\:\dfrac{y_P + y_Q}{2}\right)}[/tex]
[tex]\mathsf{C\left(\dfrac{-2 + 6}{2};\:\dfrac{3 + 1}{2}\right)}[/tex]
[tex]\mathsf{C\left(\dfrac{4}{2};\:\dfrac{4}{2}\right)}[/tex]
[tex]\mathsf{C(2;2)}[/tex]
[tex]\mathsf{(x - a)^2 + (y - b)^2 = r^2}[/tex]
[tex]\mathsf{(x - 2)^2 + (y - 2)^2 = (\sqrt{17})^2}[/tex]
[tex]\boxed{\boxed{\mathsf{(x - 2)^2 + (y - 2)^2 = 17}}}[/tex]
