[tex]\frac{\sqrt{(50-2\sqrt{2)x2} } }{2}[/tex]Resposta:
A) 0
B) [tex]\sqrt[8]{5}[/tex]
C)[tex]\sqrt{25-\sqrt{2} }[/tex]
D)
Explicação passo a passo:
A)
√18 – √8 – √2 =
[tex]\sqrt[3]{2} -\sqrt{8} -\sqrt{2}[/tex]=
[tex]\sqrt[3]{2} -\sqrt[2]{2} -\sqrt{2}[/tex]=
0
B)
5√45 + 3√5 – 2√125 =
[tex]\sqrt[15]{5}+\sqrt[3]{5} -\sqrt[2]{125}[/tex]
[tex]\sqrt[15]{5}+\sqrt[3]{5}-\sqrt[10]{5}[/tex]
[tex]\sqrt[8]{5}[/tex]
C)
√50 – √8 / √2 =
[tex]\frac{\sqrt{50 -\sqrt[2]{2} } }{\sqrt{2} }[/tex]
multiplique a fração por [tex]\frac{\sqrt{2} }{\sqrt{2} } \\[/tex]
[tex]\frac{\sqrt{50-\sqrt[2]{2 \sqrt{2} } } }{\sqrt{2} } x \frac{\sqrt{2} }{\sqrt{2} }[/tex]
[tex]\frac{\sqrt{(50-2\sqrt{2)x2} } }{\sqrt{2\sqrt{2} } }[/tex]
[tex]\frac{\sqrt{(50-2\sqrt{2)x2} } }{\s2\ } }[/tex]
[tex]\frac{\sqrt{100-4\sqrt{2} } }{2}[/tex]
[tex]\frac{2\sqrt{25-\sqrt{2} } }{2}[/tex]
[tex]\sqrt{25-\sqrt{2} }[/tex]
D)
1√7 + 3 √7 =
— —
2 2 nao entendi oque vc quis dizer...
