[tex]\large\text{$ O ~comprimento ~da ~circunfer\hat{e}ncia ~da~ base ~ \Rightarrow ~ C = 8 \pi x$}[/tex]
[tex]\large\text{$ letra ~c) ~ 8\pi x $}[/tex]
[tex]\large\text{$S\acute{o}lidos ~Geom\acute{e}tricos $}[/tex]
Encontrar o valor do raio da base do cilindro.
[tex]V = \pi~ . ~r^2~ .~ h\\\\16\pi x^3 - 48 \pi x^2 = \pi~ . ~r^2~ .~ ( x - 3) \\\\(16 x^3 - 48 x^2) \pi = \pi~ . ~r^2~ .~ ( x - 3)\\\\\pi~ . ~r^2~ .~ ( x - 3) = 16x^2\pi .(x - 3)\\\\r^2 = \dfrac{ 16x^2\pi .(x - 3)}{(x - 3)\pi } \\\\\\r^2 = 16x^2\\\\r = \sqrt{16x^2} \\\\r = 4x[/tex]
Comprimento da circunferência da base.
[tex]C = 2 ~. ~\pi ~r\\\\C = 2 \pi ~. ~4x\\\\C = 8\pi~x[/tex]
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