[tex]\large\text{$A ~soma ~dos ~termos ~da ~PG ~ \Rightarrow ~ S6 = 126$}[/tex]
[tex]\Large\text{$ Progress\tilde{a}o ~Geom\acute{e}trica $}[/tex]
Encontrar a razão da PG.
[tex]an = a1 ~. ~q^{(n - 1)}\\\\64 = 2 ~. ~q^{(6 - 1)}\\\\\dfrac{64}{2} = q^5\\\\32 = q^5\\\\q = \sqrt[5]{32} \\\\q = \sqrt[5]{2^5}\\\\q = 2[/tex]
Com a razão da PG o números de termos e o termo a1, encontrar a soma da PG
[tex]S6 = \dfrac{a1 ~\cdot~( q^n - 1) }{q - 1}\\\\\\S6 = \dfrac{2 ~\cdot~( 2^6 - 1) }{2 - 1}\\\\\\S6 = \dfrac{2 ~\cdot~( 64 - 1) }{1}\\\\\\S6 = \dfrac{2 ~\cdot~(63) }{1}\\\\\\S6 = \dfrac{126 }{1}\\\\\\S6 = 126[/tex]
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