[tex]\Huge\boxed {\large \begin{array}{l}\sf Sen(30^{o}) = \large \frac{x}{2} \\ \\ \large \sf \frac{1}{2} = \frac{x}{2} \\ \\ \sf 2x = 1 \times 2\\ \\ \sf 2x = 2 \\ \\ \sf x =\large \frac{2}{2} \\ \\ \sf x = 1 \end{array}}[/tex]
[tex]\large\boxed{\begin{array}{l}\rm seja\,h\,a\,altura\,da\,escada (cateto\,oposto\,\ao\,\hat angulo\,de\,30^\circ).\\\rm 2\,m\,\acute e\,a\,hipotenusa\\\rm a\,relac_{\!\!,}\tilde ao\,trigonom\acute etrica\,que\,envolve\,cateto\,oposto\\\rm e\,hipotenusa\,\acute e\,o\,seno.\\\rm portanto\\\rm sen(30^\circ)=\dfrac{h}{2}\\\\\rm h=2\cdot sen(30^\circ)\\\\\rm h=\backslash\!\!\!2\cdot\dfrac{1}{\backslash\!\!\!2}\\\\\rm h=1\,m\end{array}}[/tex]
[tex]\Huge\boxed{\boxed{\boxed{\boxed{\rm\dagger\red{\maltese}~\blue{alternativa~b}}}}}[/tex]
