Resposta:
b) x=-5 a) x=3/2 e x=2/3 b)x=1/4 e x= -3 c) x=1/3 e x= -1/2 d)x=1/2 e x= -3 e) x=1
f) fiquei na dúvida se era 5[tex]x^{2}[/tex]- 11[tex]x^{2}[/tex]=0 ?? ou falta o sinal antes do 2
Explicação passo a passo:
b) [tex]x^{2}[/tex] +10x+25=0 a=1 b=10 c=25 a) 6x² - 13 x + 6=0 a=6 b=-13 c=6
x=-b +- [tex]\sqrt{b^2-4*a*c}[/tex] / 2a x=-(-13)+-[tex]\sqrt{(-13)^2-4*6*6}[/tex]/2*6
x=-10+-[tex]\sqrt{10^2-4*1*25}[/tex]/2*1 x= 13+-[tex]\sqrt{169-144}[/tex]/12
x=-10+-[tex]\sqrt{100-100}[/tex]/2 x= 13+-[tex]\sqrt{25}[/tex]/12
x=-10+-0/2 x1= -10/2 = -5 x1= 13+5/12 = 18/12 = 3/4
x2= 13-5/12= 8/12 = 2/3
b)4x² + 11x-3=0 a=4 b=11 c= -3 C)6x²+ x-1=0 a=6 b=1 c=-1
x=-11+-[tex]\sqrt{(11^2)-4*4*(-3)}[/tex]/2*4 x=-1+-[tex]\sqrt{1^2-4*6*(-1)}[/tex]/2*6
X=-11+-[tex]\sqrt{121+48}[/tex]/8 x= -1+- [tex]\sqrt{1+24}[/tex]/12
X= -11+- [tex]\sqrt{169}[/tex]/8 x= -1+-[tex]\sqrt{25}[/tex]/12
X= -11+-13/8 x= -1+- 5/12
X1=-11+13/8= 2/8=1/4 x1=-1+5/12=4/12 = 1/3
X2= -11-13/8 = -24/8= -3 x2= -1-5/12 = -6/12 = -1/2
d) 2x^2+5x-3=0 a=2 b=5 c=-3 e) x²-2x+1=0 a=1 b=-2 c=1
x=-5+- [tex]\sqrt{5^2-4*2*(-3)}[/tex]/2*2 x=-(-2)+- [tex]\sqrt{(-2)^2-4*1*1}[/tex]/2*1
x=-5+-[tex]\sqrt{25+24}[/tex]/4 x= 2+- [tex]\sqrt{4-4}[/tex]/2
x=-5+-[tex]\sqrt{49}[/tex]/4 = -5+-7/4 x=2+-0/2 = 1
x1=-5+7/4=2/4=1/2
x2=-5-7/4=-12/4 =-3
