Resposta:
Explicação passo a passo:
(3^3)^2 + (2^2)^2=
3^6+2^4=
729 + 16=
745
Para resolver sua questão, vale ressaltar as seguintes propriedades:
[tex]\Large\displaystyle\text{$\begin{gathered} a^n=\underbrace{a\cdot a\cdot a\cdot a\cdot \ldots\cdot a}_{\large\displaystyle\text{$\begin{gathered} n\ vezes\end{gathered}$}}\ \ \red{(I)}.\end{gathered}$}[/tex]
[tex]\Large\displaystyle\text{$\begin{gathered} (a^b)^c = a^{bc}\ \ \red{(II)}. \end{gathered}$}[/tex]
Sabendo disso, temos que:
[tex]\Large\displaystyle\text{$\begin{gathered} (3^3)^2+(2^2)^2 = 3^{3\cdot2}+2^{2\cdot2}\end{gathered}$}[/tex]
[tex]\Large\displaystyle\text{$\begin{gathered} (3^3)^2+(2^2)^2 = 3^{6}+2^{4}\end{gathered}$}[/tex]
[tex]\Large\displaystyle\text{$\begin{gathered} (3^3)^2+(2^2)^2 = (3\cdot3\cdot3\cdot3\cdot3\cdot3)+(2\cdot2\cdot2\cdot2)\end{gathered}$}[/tex]
[tex]\Large\displaystyle\text{$\begin{gathered} (3^3)^2+(2^2)^2 = 729+16\end{gathered}$}[/tex]
[tex]\Large\displaystyle\text{$\begin{gathered}\therefore \green{\underline{\boxed{ (3^3)^2+(2^2)^2 =745}}}\ \ (\checkmark).\end{gathered}$}[/tex]
