✅ Após ter realizado os cálculos, concluímos que o ponto médio do segmento AB é:
[tex]\large\displaystyle\text{$\begin{gathered}\boxed{\boxed{\:\:\:\bf M = \Bigg(\frac{13}{2}, \frac{9}{2} \Bigg)\:\:\:}} \end{gathered}$}[/tex]
Sejam os pontos:
[tex]\large\begin{cases}A(7, 4)\\B(6, 5) \end{cases}[/tex]
As coordenada do ponto médio do segmento AB é:
[tex]\large\displaystyle\text{$\begin{gathered}M = (X_{M}, Y_{M}) \end{gathered}$}[/tex]
[tex]\large\displaystyle\text{$\begin{gathered}= \Bigg(\frac{X_{A} + X_{B}}{2}, \frac{Y_{A} + Y_{B}}{2} \Bigg) \end{gathered}$}[/tex]
[tex]\large\displaystyle\text{$\begin{gathered}= \Bigg(\frac{7 + 6}{2}, \frac{4 + 5}{2} \Bigg) \end{gathered}$}[/tex]
[tex]\large\displaystyle\text{$\begin{gathered}= \Bigg(\frac{13}{2}, \frac{9}{2} \Bigg) \end{gathered}$}[/tex]
✅ Portanto, o ponto médio é:
[tex]\large\displaystyle\text{$\begin{gathered}M = \Bigg(\frac{13}{2}, \frac{9}{2} \Bigg) \end{gathered}$}[/tex]
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Solução gráfica:
