Resposta:
[tex]\textsf{Leia abaixo}[/tex]
Explicação passo a passo:
[tex]\mathsf{-4x^2 - 2x - 3 = 0}[/tex]
[tex]\mathsf{\Delta = b^2 - 4.a.c}[/tex]
[tex]\mathsf{\Delta = (-2)^2 - 4.(-4).(-3)}[/tex]
[tex]\mathsf{\Delta = 4 - 48}[/tex]
[tex]\mathsf{\Delta = -44}[/tex]
[tex]\boxed{\boxed{\mathsf{S = \{\emptyset\}}}}[/tex]
[tex]\mathsf{x^2 - 4x - 5 = 0}[/tex]
[tex]\mathsf{\Delta = b^2 - 4.a.c}[/tex]
[tex]\mathsf{\Delta = (-4)^2 - 4.1.(-5)}[/tex]
[tex]\mathsf{\Delta = 16 + 20}[/tex]
[tex]\mathsf{\Delta = 36}[/tex]
[tex]\mathsf{x = \dfrac{-b \pm \sqrt{\Delta}}{2a} = \dfrac{4 \pm \sqrt{36}}{2} \rightarrow \begin{cases}\mathsf{x' = \dfrac{4 + 6}{2} = \dfrac{10}{2} = 5}\\\\\mathsf{x'' = \dfrac{4 - 6}{2} = -\dfrac{2}{2} = -1}\end{cases}}[/tex]
[tex]\boxed{\boxed{\mathsf{S = \{5;-1\}}}}[/tex]
