[tex] \Large\boxed{\begin{array}{l}\sf 3x+3y=7\\\sf 3\cdot(2m+1)+3\cdot(m-3)=7\\\sf 6m+3+3m-9=7\\\sf 9m-6=7\\\sf 9m=7+6\\\sf 9m=13\\\sf m=\dfrac{13}{9}\\\\\sf x=2m+1\\\sf x=2\cdot\bigg(\dfrac{13}{9}\bigg)+1\\\sf x=\dfrac{26}{9}+1=\dfrac{35}{9}\\\\\sf y=\dfrac{13}{9}-3\\\\\sf y=\dfrac{13-27}{9}\\\\\sf y=-\dfrac{14}{9}\end{array}} [/tex]
[tex]\Large\boxed {\begin{array}{l} \displaystyle \sf C\acute{a}lculo\:do\:valor\:de\:m :\\\\\displaystyle \sf3x+3y=7\\\\\displaystyle \sf 3 \cdot (2m+1)+3\cdot(m-3)=7\\\\\displaystyle \sf 6m +3+3m-9=7 \\\\\displaystyle \sf 9m-6=7\\\\\displaystyle \sf 9m = 7+6\\\\\displaystyle \sf 9=13\\\\ \displaystyle \sf m=\dfrac{13}{9} \sf\end{array}}[/tex]
[tex]\Large\boxed {\begin {array}{l} \displaystyle \sf C\acute{a}lculo\:do\:valor\:de\:x :\\\\\displaystyle\sf x=2m+1 \\ \\ \displaystyle \sf x=2\cdot \left( \dfrac{13}{9} \right) +1\\\\\displaystyle\sf x=\dfrac{26}{9} +1=\dfrac{35}{9} \sf\end{array}}[/tex]
[tex]\Large\boxed{\begin{array}{l} \displaystyle\sf C\acute{a}lculo\:do\:valor\:de\:y:\\\\\displaystyle \sf y=\dfrac{13}{9} -3\\\\\displaystyle\sf y=\dfrac{13-27}{9}\\\\\displaystyle \sf y=-\dfrac{14}{9} \sf\end{array}}[/tex]
