[tex]\large\text{$ \acute{A}rea ~da~ base ~ \Rightarrow ~Ab = 16 ~\pi ~cm^2 $}\\\\\large\text{$\acute{A}rea ~lateral ~ \Rightarrow ~Al = 160 ~\pi ~cm^2 $}\\\\\large\text{$\acute{A}rea ~Total ~ \Rightarrow ~At = 288 ~\pi ~cm^2 $}\\\\\large\text{$ Volume ~ \Rightarrow ~ V = 80 ~\pi ~cm^3$}[/tex]
Cilindro de revolução o raio da base mede 8 cm e a geratriz 10 cm:
Área da base:
[tex]Ab = 2~. ~\pi~. ~r\\\\Ab = 2~. ~\pi~. ~8\\\\Ab = 16~\pi ~cm^2[/tex]
Área lateral:
[tex]Al = 2 ~. ~\pi ~. ~r ~. ~h\\\\Al = 2 ~. ~\pi ~. ~8~. ~10\\\\Al = 2 ~. ~\pi ~. ~80\\\\Al = 160 ~\pi ~cm^2[/tex]
Área total:
[tex]At = 2 ~.~\pi ~. ~r ~. ~(r + h)\\\\ At = 2 ~.~\pi ~. ~8 ~. ~(8 + 10)\\\\ At = 16~. ~18 ~\pi\\\\At = 288 ~\pi ~cm^2[/tex]
Volume:
[tex]V = r^2 ~. ~ h~. ~ \pi\\\\V = 8 ~. ~10 ~. ~\pi\\\\V = 80 ~\pi~cm^3[/tex]
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