[tex]\large\text{$a) ~A ~\acute{a}rea ~da ~base ~ \Rightarrow ~Ab = 4 ~\pi ~cm^2$}\\\\\large\text{$b) ~~A ~\acute{a}rea ~lateral ~ \Rightarrow ~ Al = 16 ~\pi ~ cm^2$}\\\\\large\text{$c) A ~\acute{a}rea ~ total ~ \Rightarrow ~At = 24 ~\pi ~cm^2 $}[/tex]
a)
Encontrar o raio do cilindro:
[tex]r = di\hat{a}metro / 2\\\\r = 4 / 2\\\\r = 2 ~cm[/tex]
A área da base do cilindro:
[tex]Ab = \pi ~. ~r^2\\\\Ab = \pi~. ~2^2\\\\Ab = 4\pi ~cm^2[/tex]
b) a área lateral:
[tex]Al = 2\pi ~.~r ~.~ h\\\\A l = 2 . ~\pi ~2 ~. ~4\\\\Al = 2~. ~\pi ~. ~8\\\\Al = 16 ~\pi ~ cm^2[/tex]
c) a área total:
[tex]At = 2 ~.~\pi ~. ~r ~. ~(r + h)\\\\ At = 2 ~.~\pi ~. ~2 ~. ~(2 + 4) \\\\At = 4 ~.~\pi ~. ~(6) \\\\At = 24 ~\pi ~cm^2[/tex]
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