Resolução!
[tex]a = \frac{1}{2} + \frac{3}{2} = > \frac{4}{2} = 2 \\ \\ \\ b = \frac{4}{3} + \frac{5}{3} = > \frac{9}{3} = 3 \\ \\ \\ c = \frac{5}{6 } + \frac{2}{6} = \frac{7}{6} \\ \\ \\ d = \frac{1}{2} + \frac{1}{3} = = = = mmc = 6\\ \frac{3 + 2}{6} = \frac{5}{6} \\ \\ \\ e = \frac{1}{2} + \frac{1}{4} = = = = = = mmc = 4 \\ \frac{2 + 1}{4} = \frac{3}{4} \\ \\ \\ f = \frac{1}{3} + \frac{1}{4} = = = mmc = 12 \\ \frac{4 + 3}{12} = \frac{7}{12} \\ \\ \\ g = \frac{3}{4} - \frac{2}{3} = = = mmc = 12 \\ \frac{9 - 8}{12} = \frac{1}{12} \\ \\ \\ h = \frac{2}{5} - \frac{1}{3} = = = mmc = 15 \\ \frac{6 - 5}{15} = \frac{1}{15} \\ \\ \\ i = \frac{6}{4} - \frac{1}{7} + \frac{1}{2} = = = mmc = 28 \\ \frac{42 - 4 + 14}{28} = > \frac{52}{28} = \frac{13}{7} \\ \\ \\ j = \frac{4}{7} - \frac{6}{2} = = = mmc = 14 \\ \frac{8 - 42}{14} = > \frac{ - 34}{14} = \frac{ - 17}{7} \\ \\ \\ k = \frac{3}{2} - \frac{1}{19} = = = mmc = 38 \\ \frac{57 - 2}{38} = \frac{55}{38} \\ \\ \\ \\ \\ espero \: ter \: ajudado[/tex]
