Explicação passo a passo:
Olá.
Vamos resolvê-las.
A) [tex]\frac{x}{4} + 20 = \frac{x}{3} \\[/tex]
[tex]\ 3x + 240 = 4x\\\\-x + 240 = 0\\\\-x = -240\\\\x = 240[/tex]
B) [tex]\frac{2}{5}y - \frac{3}{4} = \frac{3}{20}y[/tex]
[tex]\frac{2}{5}y - \frac{3}{4} - \frac{3}{20}y = 0[/tex]
[tex]\frac{1}{4}y - \frac{3}{4} = 0[/tex]
[tex]\ y = \frac{3}{4} * 4[/tex]
[tex]\ y = 3[/tex]
C) [tex]1 - \frac{x}{2} = -\frac{1}{3}x + 2[/tex]
[tex]\ 6 - 3x = -2x + 12\\\\6 - x = 12\\\\-x = 12 - 6\\ \\-x = 6\\\\x = -6[/tex]
D) [tex]\frac{x-10}{9} + \frac{x}{6} = 10[/tex]
[tex]\ 2x - 20 + 3x = 180\\\\5x = 200\\x = 40[/tex]
E) [tex]\frac{x+3}{4}-\frac{x-1}{3}=\frac{7}{2}[/tex]
[tex]\ 3(x + 3) - 4(x - 1) = 42\\\\3x + 9 - 4x + 4 = 42\\\\-x + 13 = 42\\\\x = -29[/tex]
F) [tex]\frac{4x - 1}{10} - 2 = \frac{4}{5} - \frac{2 -x}{4}[/tex]
[tex]\ 2(4x-1)-40=16-5(2-x)\\\\8x-2-40=16-5(2-x)\\\\8x-42=16-5(2-x)\\\\8x-42=16-10+5x\\\\8x-42=6+5x\\\\8x-42-5x=6\\\\3x-42=6\\\\3x=42+6\\\\3x=48\\\\x=16[/tex]
Espero ter ajudado!
