Oie, tudo bom?
a)
[tex] = 2 - ( \frac{1}{5} + \frac{2}{7} ) \\\boxed{mmc(35)} \\ = 2 - \frac{7 + 10}{35} \\ = 2 - \frac{17}{35} \\ = \frac{70 - 17}{35} \\ \boxed{ = \frac{53}{35} }[/tex]
b)
[tex] = ( \frac{4}{3} + \frac{7}{2} ) - \frac{3}{5} \\ \boxed{mmc(6)} \\ = \frac{8 + 21}{6} - \frac{3}{5} \\ = \frac{29}{6} - \frac{3}{5} \\ \boxed{mmc(30)} \\ = \frac{145 - 18}{30} \\ \boxed{ = \frac{127}{30} }[/tex]
c)
[tex] = \frac{1}{2} \: . \: ( \frac{2}{5} + \frac{3}{4} ) \\ \boxed{mmc(20)} \\ = \frac{1}{2} \: . \: \frac{8 +15 }{20} \\ = \frac{1}{2} \: . \: \frac{23}{20} \\ = \frac{1 \: . \: 23}{2 \: . \: 20} \\ \boxed{ = \frac{23}{40} }[/tex]
d)
[tex] = ( \frac{1}{2} + \frac{3}{4} ) {}^{2} \\ \boxed{mmc(4)} \\ = ( \frac{2 + 3}{4} ) {}^{2} \\ = ( \frac{5}{4} ) {}^{2} \\ = \frac{5 {}^{2} }{4 {}^{2} } \\ \boxed{ = \frac{25}{16} }[/tex]
e)
[tex] = ( \frac{7}{5} - \frac{5}{6} ) {}^{2} \\ \boxed{mmc(30)} \\ = ( \frac{42 - 25}{30} ) {}^{2} \\ = ( \frac{17}{30} ) {}^{2} \\ = \frac{17 {}^{2} }{30 {}^{2} } \\ \boxed{ = \frac{289}{900} }[/tex]
f)
[tex] = \frac{9}{10} + ( \frac{1}{3} ) {}^{2} \\ = \frac{9}{10} + \frac{1 {}^{2} }{3 {}^{2} } \\ = \frac{9}{10} + \frac{1}{9} \\ \boxed{mmc(90)} \\ = \frac{81 + 10}{90} \\ \boxed{ = \frac{91}{90} }[/tex]
Att. NLE Top Shotta
