Resposta:
(
+
5
)
(
+
7
)
=
0
(x+5)(x+7)=0
(x+5)(x+7)=0
Função do segundo grau
Fatore
1
Aplique a propriedade distributiva
(
+
5
)
(
+
7
)
=
0
{\color{#c92786}{(x+5)(x+7)}}=0
(x+5)(x+7)=0
(
+
7
)
+
5
(
+
7
)
=
0
{\color{#c92786}{x(x+7)+5(x+7)}}=0
x(x+7)+5(x+7)=0
2
Aplique a propriedade distributiva
(
+
7
)
+
5
(
+
7
)
=
0
{\color{#c92786}{x(x+7)}}+5(x+7)=0
x(x+7)+5(x+7)=0
2
+
7
+
5
(
+
7
)
=
0
{\color{#c92786}{x^{2}+7x}}+5(x+7)=0
x2+7x+5(x+7)=0
3
Aplique a propriedade distributiva
2
+
7
+
5
(
+
7
)
=
0
x^{2}+7x+{\color{#c92786}{5(x+7)}}=0
x2+7x+5(x+7)=0
2
+
7
+
5
+
3
5
=
0
x^{2}+7x+{\color{#c92786}{5x+35}}=0
x2+7x+5x+35=0
4
Combine os termos semelhantes
2
+
7
+
5
+
3
5
=
0
x^{2}+{\color{#c92786}{7x}}+{\color{#c92786}{5x}}+35=0
x2+7x+5x+35=0
2
+
1
2
+
3
5
=
0
x^{2}+{\color{#c92786}{12x}}+35=0
x2+12x+35=0
5
Use a função do segundo grau
=
−
±
2
−
4
√
2
x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}
x=2a−b±b2−4ac
Na forma padrão, identifique "a", "b" e "c" da equação original e adicione esses valores à função do segundo grau.
2
+
1
2
+
3
5
=
0
x^{2}+12x+35=0
x2+12x+35=0
=
1
a={\color{#c92786}{1}}
a=1
=
1
2
b={\color{#e8710a}{12}}
b=12
=
3
5
c={\color{#129eaf}{35}}
c=35
=
−
1
2
±
1
2
2
−
4
⋅
1
⋅
3
5
√
2
⋅
1
x=\frac{-{\color{#e8710a}{12}} \pm \sqrt{{\color{#e8710a}{12}}^{2}-4 \cdot {\color{#c92786}{1}} \cdot {\color{#129eaf}{35}}}}{2 \cdot {\color{#c92786}{1}}}
x=2⋅1−12±122−4⋅1⋅35
Mais 3 etapas
Solução
=
−
5
=
−
7
