✅ Após resolver os cálculos, concluímos que a soma dos polinômios é:
[tex]\Large\displaystyle\text{$\begin{gathered}\boxed{\boxed{\:\:\:\bf S(x) = x^{2} + 7x + 9\:\:\:}}\end{gathered}$}[/tex]
Sejam os polinômios:
[tex]\Large\begin{cases} P(x) = x^{2} + 3x - 1\\Q(x) = 4x + 10\end{cases}[/tex]
Calculando a soma "S(x)" dos polinômios, temos:
[tex]\Large\displaystyle\text{$\begin{gathered} S(x) = P(x) + Q(x)\end{gathered}$}[/tex]
[tex]\Large\displaystyle\text{$\begin{gathered} = (x^{2} + 3x - 1) + (4x + 10)\end{gathered}$}[/tex]
[tex]\Large\displaystyle\text{$\begin{gathered} = x^{2} + 3x - 1 + 4x + 10\end{gathered}$}[/tex]
[tex]\Large\displaystyle\text{$\begin{gathered} = x^{2} + 7x + 9\end{gathered}$}[/tex]
✅ Portanto, a soma dos polinômios é:
[tex]\Large\displaystyle\text{$\begin{gathered} S(x) = x^{2} + 7x + 9\end{gathered}$}[/tex]
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