Resposta:
[tex](\frac{9}{5} -\frac{3}{10}) \div 3\frac{1}{2}+0,4\\\\por\ partes\\\\(\frac{9}{5} -\frac{3}{10})\\\\mmc = 10\\\\\frac{9\cdot2-3}{10}\\\\\frac{15}{10} (\div5) = \frac{3}{2}\\\\ 3\frac{1}{2} \\\\ \frac{3\cdot2+1}{2}\\\\ \frac{7}{2}\\\\0,4\\\\\frac{4}{10} \\\\\frac{4}{10} (\div2)\\\\\frac{2}{5}\\\\Remontando\\\\\frac{3}{2} \div\frac{7}{2}+ \frac{2}{5}\\\\\frac{3\cdot2}{2\cdot7} + \frac{2}{5}\\\\\frac{3}{7}+ \frac{2}{5} \\\\mmc=45\\\\\frac{3\cdot5+2\cdot7}{45} \\\\\frac{15+14}{45}\\\\[/tex]
[tex]\frac{19}{45}[/tex]
Explicação passo-a-passo:
