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[tex]\Large\boxed{\begin{array}{l}\sf Seja~A(x_A,y_A)~e~B(x_B,y_B).\\\sf o~ponto~m\acute edio~de~A~e~B~a~qual~representa-se\\\sf M(x_M,y_M)~\acute e~dado~por\\\boxed{\boxed{\boxed{\boxed{\sf x_M=\dfrac{x_A+x_B}{2}}}}}~\rm e~\boxed{\boxed{\boxed{\boxed{\sf y_M=\dfrac{y_A+y_B}{2}}}}}\end{array}}[/tex]
[tex]\Large\boxed{\begin{array}{l}\sf Dado~um~ponto~A(x_A,y_A)\\\sf a~dist\hat ancia~de~A~at\acute e~a~origem~\acute e~dada~por\\\huge\boxed{\boxed{\boxed{\boxed{\sf d=\sqrt{x_A^2+y_B^2}}}}}\end{array}}[/tex]
[tex]\underline{\rm observe~a~figura~que~anexei.}\\\sf a~soluc_{\!\!,}\tilde ao~consiste~em~achar~a~dist\hat ancia~do~ponto~m\acute edio~de~B~e~C\\\sf a~origem.\\\sf x_M=\dfrac{3+5}{2}=\dfrac{8}{2}=4\\\sf y_M=\dfrac{7+(-1)}{2}=\dfrac{7-1}{2}=\dfrac{6}{2}=3\\\sf M(4,3)\\\overline{\sf AM}=\sqrt{4^2+3^2}\\\overline{\sf AM}=\sqrt{16+9}\\\overline{\sf AM}=\sqrt{25}\\\huge\boxed{\boxed{\boxed{\boxed{\overline{\sf AM}=\sf5~u\cdot c}}}}[/tex]
