Descubra respostas para suas perguntas no Sistersinspirit.ca, a plataforma de Q&A mais confiável e eficiente para todas as suas necessidades. Descubra respostas abrangentes para suas perguntas de profissionais experientes em nossa plataforma amigável. Descubra soluções abrangentes para suas perguntas de profissionais experientes em nossa amigável plataforma.

Enumere a primeira coluna de acordo com segunda coluna de o valor da raiz de x: ( 1 ) 12x² = 0;
( 2 ) x² - 64 = 0
( 3 ) x² - 1 = 0
( 4 ) x² -2 x = 0
( 5 ) 12x² - 48 = 0
( ) ( +8, -8 )
( ) ( 0, 0 )
( ) ( 0 ,+ 2)
( ) ( +1, -1 )
( ) ( + 2, - 2 )

d ) 2 – 1 – 4 – 3 – 5; c ) 2 – 4 – 1 – 5 – 3; a) 5 – 2 – 1 – 4 – 3; b ) 4 – 2 – 1 – 3 – 5;


Sagot :

Resolvendo as equações primeiro:

( 1 )

[tex]\begin{array}{l}\sf 12x^2=0\\\\\sf \dfrac{12x^2}{12}=\dfrac{0}{12}\\\\\sf x^2=0\\\\\sf \sqrt{x^2}=\sqrt{0}\\\\\sf |x|=0\\\\\sf \therefore~x'=x''~\Rightarrow~0\end{array}[/tex]

( 2 )

[tex]\begin{array}{l}\sf x^2-64=0\\\\\sf 64+x^2-64=0+64\\\\\sf x^2=64\\\\\sf \sqrt{x^2}=\sqrt{64}\\\\\sf |x|=8\\\\\sf x=\pm~8\\\\\sf \therefore~x'=8\quad e\quad x''=-8\end{array}[/tex]

( 3 )

[tex]\begin{array}{l}\sf x^2-1=0\\\\\sf 1+x^2-1=0+1\\\\\sf x^2=1\\\\\sf \sqrt{x^2}=\sqrt{1}\\\\\sf |x|=1\\\\\sf x=\pm~1\\\\\sf \therefore~x'=1\quad e\quad x''=-1\end{array}[/tex]

( 4 )

[tex]\begin{array}{l}\sf x^2-2x=0\\\\\sf x(x-2)=0\\\\\begin{cases}\sf x=0\\\\\sf x-2=0\end{cases}\\\\\begin{cases}\sf x'=0\\\\\sf x''=2\end{cases}\end{array}[/tex]

( 5 )

[tex]\begin{array}{l}\sf 12x^2-48=0\\\\\sf 48+12x^2-48=0+48\\\\\sf 12x^2=48\\\\\sf \dfrac{12x^2}{12}=\dfrac{48}{12}\\\\\sf x^2=4\\\\\sf \sqrt{x^2}=\sqrt{4}\\\\\sf |x|=2\\\\\sf x=\pm~2\\\\\sf \therefore~x'=2\quad e\quad x''=-2\end{array}[/tex]

Assim relacionando a primeira coluna com a segunda:

( 2 ) => S = {8 ; -8}

( 1 ) => S = { 0 }

( 4 ) => S = {0 ; 2}

( 3 ) => S = {1 ; - 1}

( 5 ) => S = {2 ; -2}

RESPOSTA: dessa forma a alternativa que se encaixa é: Letra D)

Att. Nasgovaskov

View image Nasgovaskov